3x+2y[x+y(x-3y)-y^2]=

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Solution for 3x+2y[x+y(x-3y)-y^2]= equation: 


Simplifying
3x + 2y[x + y(x + -3y) + -1y2] = 0
3x + 2y[x + (x * y + -3y * y) + -1y2] = 0
3x + 2y[x + (xy + -3y2) + -1y2] = 0

Combine like terms: -3y2 + -1y2 = -4y2
3x + 2y[x + xy + -4y2] = 0
3x + [x * 2y + xy * 2y + -4y2 * 2y] = 0
3x + [2xy + 2xy2 + -8y3] = 0

Solving
3x + 2xy + 2xy2 + -8y3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8y3' to each side of the equation.
3x + 2xy + 2xy2 + -8y3 + 8y3 = 0 + 8y3

Combine like terms: -8y3 + 8y3 = 0
3x + 2xy + 2xy2 + 0 = 0 + 8y3
3x + 2xy + 2xy2 = 0 + 8y3
Remove the zero:
3x + 2xy + 2xy2 = 8y3

Combine like terms: 8y3 + -8y3 = 0
3x + 2xy + 2xy2 + -8y3 = 0

The solution to this equation could not be determined.

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